Question

what should be subtracted from (5by 14 + 3 by 7 ) to get 1 by 5?​

Answer 1

Answer:

5/14 + 3/7 should be subtracted to 1/5

5/14 + 3/7 - 1/5

Now take the LCM of 14, 7 and 5 and we get 70

=25 + 30 - 14/70

=55 - 14/70

= 41/70

41/70 should be subracted from 5/14+3/7 to get 1/5.

Step-by-step explanation:

Answer 2

Answer :

$\frac{41}{70}$ is the number that should be subtracted from the sum of $\frac{5}{14}$ and $\frac{3}{7} to\:get \: \frac{1}{5}$ .

Step by step explanation-

To find-

• What number should be subtracted from the sum of $\frac{5}{14}$ and $\frac {3}{7} to\: get \frac{1}{5}$ ?

How to solve?

• At first we'll take that number as x and will form the equation to find the value of x.

• Then we'll add $\frac{5}{14}$ and $\frac{3}{7}$ as per to find their sum and then we'll find the value of x by transposition.

Solution-

Let the number be x.

According to question-

$\sf {⟶( \frac{5}{14} + \frac{3}{7} ) -x= \frac{1}{5}}$

(Solving bracket)

$\sf { ⟶(\frac{5 + 6}{14} ) - x = \frac{1}{5}}$

$\sf {⟶ \frac{11}{14} - x = \frac{1}{5}}$

$\sf {⟶x = \frac{11}{14} - \frac{1}{5}}$

$\sf {⟶x = \frac{41}{70}}$

So the value of x is $\frac{41}{70}$.

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