Question

what. should be subtracted from 5x^2 -6y^2+7xy+19yo obtain 3x^2-2y^2+4 xy+31​

Answer 1

Answer:

2x²- 4y² -10xy -12

Step-by-step explanation:

Let the number subtracted be p

5x²-6y²+7xy+19 - p = 3x²-2y²+4xy+31

-p = 3x²-2y²+4xy+31 - (5x²-6y²+7xy+19)

-p= 3x²-2y²+4xy+31 -5x²+ 6y² -7xy -19

-p= -2x² + 4y² +10xy+12

p = -(-2x²+ 4y²+10xy+12)

p= 2x²- 4y² -10xy -12