Math, asked by abbasshabnam154, 6 months ago

What should be subtracted from 5x²-6y²+7xy+19 to obtain 3x²-2y² +4xy+31​

Answers

Answered by parzival3620
11
Let the number be x
So
(5x^2-6y^2+7xy+19)-x=3x^2-2y^2+4xy+31
(5x^2-6y^2+7xy+19)-(3x^2-2y^2+4xy+31)
=x
5x^2-6y^2+7xy+19-3x^2-2y^2+4xy+31=x
2x^2-8y^2+11xy+50=x
I hope this helps
Please mark me as the brainiest

Similar questions