Question

what should be subtracted from (a^+b^2+c^2-ab-bc-g) to get (ab+bc+ca+abc+y) ?​

Answer 1

Answer:

Step-by-step explanation:

a²+b²+c²-ab-bc-g-x=ab+bc+ca+abc+y

-x=ab+bc+ca+abc+y-a²-b²-c²+ab+bc+g

-x=2ab+2bc+ca+g+y-a²-b²-c²

x=a²+b²+c²-2ab-2bc-ca-g-y

Answer 2

-ca-abc-y+a²+b²+c²-2ab-2bc-g

sorry :(, my fault