Question

what should be subtracted from a3-4a2+5a-6 to obtain a2-2a+1

Answer 1

Step-by-step explanation:

a^3 - 4 a^2 + 5a - 6

(subtract) --- a^2 - 2a + 1

= a^3 - 5 a^2 + 7a - 7

# when subtract or addition feature that might be multiple both the sing.

changes the sign

So,

here subtract

a3 - 5a2+7a-7

Answer 2

Given,

• The two algebraic expressions $a^3 - 4a^2+5a-6$  and  $a^2-2a+1$ are given.

To find,

• What should be subtracted from  $a^3 - 4a^2+5a-6$  to obtain  $a^2-2a+1$ .

Solution,

$a^3-5a^2+7a-7$should be subtracted from $a^3 - 4a^2+5a-6$  to obtain  $a^2-2a+1$ .

Let the polynomial that should be subtracted from $a^3 - 4a^2+5a-6$  to obtain  $a^2-2a+1$ be x.

According to the given condition,

         $a^3-4a^2+5a-6 -x = a^2 -2a+1$

Shifting the terms from LHS to RHS, we get

                                      $-x = a^2 -2a +1-a^3+4a^2-5a+6$

Simplifying the like terms, we get

                                      $-x = -a^3+5a^2-7a+7$

Taking (-) common from RHS, we get

                                      $-x = -(a^3-5a^2+7a-7)$

                                       $x = a^3-5a^2+7a-7$

Hence, $a^3-5a^2+7a-7$ should be subtracted from $a^3 - 4a^2+5a-6$  to obtain  $a^2-2a+1$ .