Question

What should be subtracted from both the numbers which are in the ratio 3: 4 so that the ratio
becomes 2:32
(A) 4
(B) 6
(C)10
(D) cannot be determined​

Answer 1

Answer:

11/16

I hope this helps you

Answer 2

$Given \: ratio = 3:4$

$Let \: x \: should \: be \: subtracted \: from$

$both \: the \: numbers = 2 : 32$

$\frac{3-x}{4-x} = \frac{2}{32}$

$\implies \frac{3-x}{4-x} = \frac{1}{16}$

$\implies 16(3-x) = 4-x$

$\implies 48 - 16x = 4 - x$

$\implies - 16x + x = 4 - 48$

$\implies - 15x = - 44$

$\implies x = \frac{-44}{-15}$

$\implies x = \frac{44}{15}$

Therefore.,

$Option \: \pink{ ( D ) } \: is \: correct.$

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