what should be subtracted from each of the numbers 54, 71,75,99 sothat the remainders may be proportional
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vivek35340:
hy
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Let x be the number to be subtracted from 71, 75, 54 and 99 so that the remainder be in proportion.
So, the remainders are (71-x), (75 -x), (54-x) and (99-x)
71−x75−x=54−x99−x
⇒ (71−x)(99−x)=(54−x)(75−x)
x2−170x+7029 =x2−129x+4050
170x−129x=7029−4050
41x =2979
x=297941 =722741
I hope it helps!
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