Math, asked by shaista81, 11 months ago

what should be subtracted from each of the numbers 54, 71,75,99 sothat the remainders may be proportional​

Answers

Answered by vivek35340
0

Answer:

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vivek35340: hy
Answered by ngarciafc10
1

Answer:

Let x be the number to be subtracted from 71, 75, 54 and 99 so that the remainder be in proportion.

So, the remainders are (71-x), (75 -x), (54-x) and (99-x)

71−x75−x=54−x99−x

⇒ (71−x)(99−x)=(54−x)(75−x)

x2−170x+7029 =x2−129x+4050

170x−129x=7029−4050

41x =2979

x=297941 =722741

I hope it helps!

Step-by-step explanation:


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