what should be subtracted from each of the numbers 54,71,75,99 so that the reminders may be proportional?
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Assume that x be number subtracted from each of the numbers 54,71,75 and 99 so that the remainders may be proportion.
∴ 54 - x , 71 - x , 75 - x , and 99 - x are in proportion.
(54 - x) / (71 - x) = (75 - x) / ( 99 - x)
(54 - x)( 99 - x) = (75 - x) (71 - x)
x2 - 99x - 54x + 5346 = x2 - 75x - 71x + 5325
(x² cancel from both side)
- 153x + 5346 = -146x + 5325
153x- 146x = 5346 - 5325
7x = 21
∴ x = 3.
∴ When x = 3 subtracted from each of the numbers so that the remainders may be proportion.
are u understand?
∴ 54 - x , 71 - x , 75 - x , and 99 - x are in proportion.
(54 - x) / (71 - x) = (75 - x) / ( 99 - x)
(54 - x)( 99 - x) = (75 - x) (71 - x)
x2 - 99x - 54x + 5346 = x2 - 75x - 71x + 5325
(x² cancel from both side)
- 153x + 5346 = -146x + 5325
153x- 146x = 5346 - 5325
7x = 21
∴ x = 3.
∴ When x = 3 subtracted from each of the numbers so that the remainders may be proportion.
are u understand?
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