Question

What should be subtracted from
I+m-m² to get 2m+ m²​

Answer 1

Answer:

Answer is -m-4m^2+l

Step-by-step explanation:

lets consider the number as x so,

l+m-m^2-x = 2m+m^2

l+m-x = 2m+m^2+m^2

l+m-x = 2m+4m^2

l-x = 2m-m+4m^2

l-x = m+4m^2

-x = m+4m^2-l

if -x = m+4m^2-l so x = -m-4m^2+l

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Answer 2

Answer:

this is the answer of your questions

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