Math, asked by ameyaalsundekar3116, 8 months ago

What should be subtracted from polynomial p (x)=2x^3-7x^2+13x+8 so that it is exactly divisible by x +6

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Answered by Uditdon6666
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What should be subtracted from polynomial p (x)=2x^3-7x^2+13x+8 so that it is exactly divisible by x +6What should be subtracted from polynomial p (x)=2x^3-7x^2+13x+8 so that it is exactly divisible by x +6What should be subtracted from polynomial p (x)=2x^3-7x^2+13x+8 so that it is exactly divisible by x +6What should be subtracted from polynomial p (x)=2x^3-7x^2+13x+8 so that it is exactly divisible by x +6What should be subtracted from polynomial p (x)=2x^3-7x^2+13x+8 so that it is exactly divisible by x +6

What should be subtracted from polynomial p (x)=2x^3-7x^2+13x+8 so that it is exactly divisible by x +6What should be subtracted from polynomial p (x)=2x^3-7x^2+13x+8 so that it is exactly divisible by x +6

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