What should be subtracted from the polynomial x + 2x + 8x +22x + 18 so that it is completely divisible
by x2 + 6 ?
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By using long division method show that x minus 3 is a factor of 6 + X - 4 x square + x cube
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Answer:
I think your question is
What should be subtracted from the polynomial x4+2x3+8x2+22x+18\text{What should be subtracted from the polynomial $x^4+2x^3+8x^2+22x +18$}What should be subtracted from the polynomial x
4
+2x
3
+8x
2
+22x+18
so that it is completely divisible by ?x2+6\text{so that it is completely divisible by $x^2 + 6$?}so that it is completely divisible by x
2
+6?
First we find the remainder when x4+2x3+8x2+22x+18\text{First we find the remainder when }x^4+2x^3+8x^2+22x +18First we find the remainder when x
4
+2x
3
+8x
2
+22x+18 is divided by using long division methodx2+6\text{ is divided by $x^2 + 6$ using long division method} is divided by x
2
+6 using long division method
The remainder we obtain from long division is 10x+6\text{The remainder we obtain from long division is 10x+6}The remainder we obtain from long division is 10x+6
∴10x+6 should be subtracted from\therefore\text{10x+6 should be subtracted from}∴10x+6 should be subtracted from x4+2x3+8x2+22x+18x^4+2x^3+8x^2+22x +18x
4
+2x
3
+8x
2
+22x+18 so that it is completely divisible byx2+6\text{so that it is completely divisible by}x^2 + 6so that it is completely divisible byx
2
+6