Question

What should be subtracted from the polynomial x4 + 2x3 + x2

– 18x – 15 so that the

resulting polynomial is exactly divisible by x2

- 1 – x.​

Answer 1

Answer:

soory I can't understand

Answer 2

Solution :-

Dividing the given polynomial x⁴ + 2x³ + x² - 18x - 15 by (x² - x - 1) we get,

x² - x - 1 ) x⁴ + 2x³ + x² - 18x - 15 ( x² + 3x + 5

x⁴ - x³ - x²

3x³ + 2x² - 18x

3x³ - 3x² - 3x

5x² - 15x - 15

5x² - 5x - 5

-10x - 10

we get,

→ Quotient = x² - x - 1

→ Remainder = -10(x + 1)

therefore, we can conclude that, when we subtract remainder from given polynomial it will exactly divisible by x² - 1 - x .

Hence, required answer will be -10(x + 1) .

Learn more :-

JEE mains Question :-

https://brainly.in/question/22246812

. Find all the zeroes of the polynomial x4

– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.

https://brainly.in/question/39026698