Math, asked by jasleenkaur12052008, 3 months ago

what should be subtracted from the product of 3/7&2/5to get -4/35​

Answers

Answered by TwilightShine
29

Answer :-

  • 2/7 should be subtracted from the product of 3/7 and 2/5 to get -4/35.

To find :-

  • The number which should be subtracted from the product of 3/7 and 2/5 to get -4/35.

Step-by-step explanation :-

  • Before finding the required number, let's find the product of 3/7 and 2/5.

-----------------------------------

: \longmapsto\sf \dfrac{3}{7}  \times  \dfrac{2}{5}

 \sf:  \longmapsto \dfrac{6}{35}

-----------------------------------

Now,

  • The product of 3/7 and 2/5 is 6/35. So we have to find the number which should be subtracted from 6/35 to get -4/35.

Let :-

  • The required number be "x".

It has been given that :-

  • When "x" is subtracted from 6/35, the result is -4/35.

Therefore,

 \tt:  \longmapsto  \dfrac{6}{35}  - x =   \dfrac{ - 4}{ \:  \: 35}

 \tt  : \longmapsto  \dfrac{6}{35}  =  \dfrac{ - 4}{ \:  \: 35}  + x

 \tt : \longmapsto \dfrac{6}{35}  -  \dfrac{ - 4}{ \:  \: 35}  = x

 \tt :\longmapsto  \dfrac{6 \times 1 - ( - 4) \times 1}{35}  = x

 \tt : \longmapsto \dfrac{6 - ( - 4)}{35}  = x

 \tt: \longmapsto \dfrac{10}{35}  = x

 : \longmapsto \underline{\boxed{\tt \dfrac{2}{7}  = x}}

________________________________

  • Hence, the required number is 2/7.
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