Math, asked by Busharani, 1 year ago

what should be subtracted from the product of 3/7 and -5/18 to get 5/42

Answers

Answered by Anonymous
5
Hey there!!

Let the number be x which should be subtracted from the product of 3/7 and -5/18 to get 5/42.

=) [(3/7) * (-5/18)] - x = 5/42

=) - 5/42 - x = 5/42

=) - 5/42 - 5/42 = x

=) - 10/42 = x

=) - 5/21 = x

To check :

=) (3/7) * (-5/18) - (-5/21) = 5/42

=) - 5/42 + 5/21 = 5/42

=) 5/42 = 5/42

=) Lhs = Rhs

Hence x = - 5/21

Hope it helps uh!!
Answered by fanbruhh
3


 \huge \bf{hey}


 \huge{ \mathfrak{here \: is \: answer}}


let the number be x which should be subtracted from the product of 3/7 and -5/18 to get 5/42

hence


 \frac{3}{7}  \times  \frac{ - 5}{18}  - x =  \frac{5}{42}


 =  \:   \frac{ - 5}{42} - x =  \frac{5}{42}


 =  \:  \frac{ - 5}{42}  -  \frac{5}{42}  = x


  =  \frac{ - 10}{42}  = x

 =  \frac{ - 5}{21}  = x

 \bf{hence \:  \frac{ - 5}{21} \: is \: answer}


 \huge{hope \: it \: helps}
 \huge{ \mathbb{THANKS}}
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