what should be subtracted from the product of 3/7 and -5/18 to get 5/42
Answers
Answered by
5
Hey there!!
Let the number be x which should be subtracted from the product of 3/7 and -5/18 to get 5/42.
=) [(3/7) * (-5/18)] - x = 5/42
=) - 5/42 - x = 5/42
=) - 5/42 - 5/42 = x
=) - 10/42 = x
=) - 5/21 = x
To check :
=) (3/7) * (-5/18) - (-5/21) = 5/42
=) - 5/42 + 5/21 = 5/42
=) 5/42 = 5/42
=) Lhs = Rhs
Hence x = - 5/21
Hope it helps uh!!
Let the number be x which should be subtracted from the product of 3/7 and -5/18 to get 5/42.
=) [(3/7) * (-5/18)] - x = 5/42
=) - 5/42 - x = 5/42
=) - 5/42 - 5/42 = x
=) - 10/42 = x
=) - 5/21 = x
To check :
=) (3/7) * (-5/18) - (-5/21) = 5/42
=) - 5/42 + 5/21 = 5/42
=) 5/42 = 5/42
=) Lhs = Rhs
Hence x = - 5/21
Hope it helps uh!!
Answered by
3
let the number be x which should be subtracted from the product of 3/7 and -5/18 to get 5/42
hence
Similar questions