Question

what should be subtracted from thrice the rational number-8/3to get 5/2​

Answer 1

$\frac{21}{-2}$ or - 10.5 is subtracted from thrice the rational number $\frac{-8}{3}$ to get $\frac{5}{2}$​.

Given:

A condition is given in which a number is subtracted from three times the $\frac{-8}{3}$ gives result equal to $\frac{5}{2}$​.

To determine:

The value of the number (n) needs to find out.

Solution:

Let's assume that the unknown number which needs to be calculated is n.

According to the condition given in the question that this number (n) is subtracted from three times the $\frac{-8}{3}$ gives $\frac{5}{2}$​. So, making the equation as:

⇒ 3 × ($\frac{-8}{3}$) - n =  $\frac{5}{2}$​.

⇒ -8 - n =  $\frac{5}{2}$​.

So, multiply 2 on both sides.

⇒ $2$ × (-8 - n) = $2$ × $\frac{5}{2}$​.

⇒ -16 -2n = 5

⇒ -2n = 5 + 16

⇒ -2n = 21

⇒ n = $\frac{21}{-2}$ = - 10.5.

Hence, 10.5  or $\frac{21}{-2}$  is the number subtracted from three times the rational number $\frac{-8}{3}$ and gives the resultant $\frac{5}{2}$​.

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