Question

What should be subtracted from twice the rational numbers 8 by 4 to get 6 by 2?

Answer 1

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$\underline{\red{ \bf Question} }$

• What Should be subtracted from twice the rational numbers $\bf \dfrac{8}{4}$ to get $\bf \dfrac{6}{2}$ ?

$\underline{ \underline{\purple { \sf To \: Find}}}$

• Value of x

$\red{\sf Let \: the \: required \: number \: be \: x}$

$\pink{ \bf A/q}$

$\purple{ \tt \implies 2( \dfrac{8}{4} ) - x = \dfrac{6}{2} }$

$\purple{ \tt \implies \cancel{ \dfrac{16}{4} } - x = \cancel{\dfrac{6}{2} }}$

$\purple{ \tt \implies 4 - x = 3}$

$\purple{ \tt \implies 4 - 3 = x}$

$\purple{ \tt \implies x = 1}$

$\underline{ \underline{\purple{ \sf Verification}}}$

$\green{ \tt \implies 2( \dfrac{8}{4} ) - 1 = \dfrac{6}{2} }$

$\green{ \tt \implies \cancel{\dfrac{16}{4}} - 1 = \cancel{\dfrac{6}{2} }}$

$\green{ \tt \implies 4 - 1 = 3}$

$\green{ \tt \implies 3 = 3}$

$\red { \bf \dag \: Proved \: \dag }$

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