what should be subtracted from x/y to make it y/x?
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x/y-b=y/x
x/y-y/x=b
x^2-y^2/xy=b
now put the value of b in first eq
x/y-(x^2-y^2/xy)=y/x
x/y-x^2+y^2/xy=y/x
x^2-x^2+y^2/xy=y/x
y^2/xy=y/x
y/x=y/x
x/y-y/x=b
x^2-y^2/xy=b
now put the value of b in first eq
x/y-(x^2-y^2/xy)=y/x
x/y-x^2+y^2/xy=y/x
x^2-x^2+y^2/xy=y/x
y^2/xy=y/x
y/x=y/x
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