Question

What should be taken away from 3x^2-4y^2+5xy+20 to get-x^2-y^2+6xy+20

Answer 1

Answer:

8x^2-3y^2-xy

Step-by-step explanation:

(3x^2-4y^2+5xy+20)-(?)= (-x^2-y^2+6xy+20)

-?= (-x^2-y^2+6xy+20)-(3x^2-4y^2+5xy+20)

?=(3x^2-4y^2+5xy+20)-(-x^2-y^2+6xy+20)

?=3x^2-4y^2+5xy+20+x^2+y^2-6xy-20

?=8x^2-3y^2-xy

Hence, 8x^2-3y^2-xy should be taken away from 3x^2-4y^2+5xy+20 to get-x^2-y^2+6xy+20.

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