Question

What should be taken away from 3x^2 - 4y^2 + 5xy + 20 to obtain -x^2 -y^2 +6xy +20?

Answer 1

Answer:

$3x^2 - 4y^2 + 5xy + 20 - (-x^2 -y^2 +6xy +20)\\=3x^2 - 4y^2 + 5xy + 20 +x^2 +y^2 -6xy -20\\= 4x^{2} -3y^{2} -xy$

Step-by-step explanation:

Answer 2

Answer:

let the desired number be k

so, (3x^2 - 4y^2 + 5xy + 20) - k = -x^2 - y^2 + 6xy + 20

- k = -x^2 - 3x^2 - y^2 + 4y^2 + 6xy - 5xy + 20 - 20

- k = -4x^2 + 3y^2 + xy

k = 4x^2 + 3y^2 + xy

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