What should be taken away from 3x ^2 − 6y ^2 + 4xy + 15 to obtain − x ^2 − y ^2 + 2xy + 12?
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Answer:
4x^2-5y^2+2xy+3
Step-by-step explanation:
3x^2-6y^2+4xy+15-(-x^2-y^2+2xy+12)
= 3x^2-6y^2+4xy+15+x^2+y^2-2xy-12
=4x^2-5y^2+2xy+3
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