Question

what should be taken away from 3x²-4x²+5xy+20 to obtain -x²-y²+6xy+20​

Answer 1

Answer:

answering the question

Answer 2

(3x^2-4y^2+5xy+20) + (-x^2-y^2+6xy+20)

= 3x^2-4y^2+5xy+20-x^2-y^2+6xy+20

= 2x^2-5y^2+11xy+40

ANS: (2x^2-5y^2+11xy+40) should be taken away from 3x²-4x²+5xy+20 to obtain -x²-y²+6xy+20.

hope my answer helps you!