Question

What should be taken away from 3x²-
4y+5xy+20 to get -x²-y²+6xy+20

Answer 1

Answer:

$4x^{2}$-4y-1xy+$y^{2}$

Step-by-step explanation:

=3$x^{2}$-4y+5xy+20+$x^{2}$+$y^{2}$-6xy-20

=3$x^{2}$+$x^{2}$= 4$x^{2}$

= -4y

= 5xy-6xy= -1xy

=20-20= 0

=  $4x^{2}$-4y-1xy+$y^{2}$

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Hope it helps ;-)