what should be taken away from (3x²-4y²+2) to obtain (-x²+y²)
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Answer:
Hence, we have to y(x) = 4x² – 3y² - xy taken away from f(x) = 3x² – 4y² + 5xy + 20 to get g(x) = – x² – y² + 6xy+ 20
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Let the number to be subtracted be = a
(3x²- 4y² + 2) - a = (-x²+y²)
3x²- 4y² + 2 - (- x² + y²) = a
3x²- 4y² + 2 + x² - y² = a
3x² + x² - 4y² - y² + 2 = a
4x² - 5y² + 2 = a
The number is 4x² - 5y² + 2
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