what should be taken away from 3x2 - 4y2 + 5xy + 20 to get-x2-y2+ 6xy+20
Answers
Answered by
2
Step-by-step explanation:
Let the requried expression be (?)
Then,
(3x²-4y²+5xy+20)-(?)=x²-y²+6xy +20
-(?)=(x²-y²+6xy+20)-(3x²-4y²+5xy+20)
-(?)=(-2x²+3y²+xy)
?=2x²-3y²-xy
By:D.Kamal(hitmanbeastman50)
Answered by
2
Answer:
Hope it can help you....
Please mark me as a brainlist...
Attachments:
Similar questions