Question

What should be taken away from (3x2 – 4y2 + 5xy +20) to obtain (– x2 – y2 +6xy +20)?

Answer 1

Answer:

4y²-3y²-xy

Step-by-step explanation:

3x2 – 4y2 + 5xy +20) - (– x2 – y2 +6xy +20)

=4y²-3y²-xy

Answer 2

(3x^2 - 4y^2 + 5xy +20) - A = (-x^2 - y^2 + 6xy + 20)

=> 3x^2 - 4y^2 + 5xy + 20 + x^2 + y^2 - 6xy - 20 = A

=> 4x^2 - 3y^2 - xy (Ans)

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Thanks!

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