Question

What should be taken away from 3x2 – 4y2 + 5xy + 20 to obtain – x2 – y2 + 6xy + 20?​

Answer 1

Answer:

Let,

(3x²-4y²+5xy+20) – (A) =( -x²-y²+6xy+20)

A =( 3x²-4y²+5xy+20) – ( -x²-y²+6xy+20)

A=( 3x²-4y²+5xy+20+x²+y²-6xy-20)

A= 4x²–3y²–xy (Ans.)