Question

What should be taken away from 3x2 - 4y2 + 5xy + 20 to obtain x2 - y2 - 6xy + 20?

Answer 1

$hope \: it \: helps \: .$

Answer 2

Answer:

let the polynomial to be taken as = a

Now, ATQ,

     => ( 3x² - 4y² + 5xy + 20 ) - a =  ( x² - y² - 6xy + 20 )

     => a =  ( 3x² - 4y² + 5xy + 20 ) - ( x² - y² - 6xy + 20 )

     => a = 3x² - 4y² + 5xy + 20 - x² + y² + 6xy - 20

     => a = 2x² - 3y² + 11xy  

Therefore, 2x² - 3y² + 11xy be taken away from 3x2 - 4y2 + 5xy + 20 to obtain x2 - y2 - 6xy + 20 . (Ans.)

                                               Hope it helps

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