Question

what should be taken away from 3x2-4y2+5xy+20 to obtain x2-y2+6xy+20​

Answer 1

Answer:

Let q should be subtracted.

Then according to question,

$3x2−4y2+5xy+20−q= \\ −x2−y2+6xy+20 \\ </u></strong></p><p><strong><u>[tex]3x2−4y2+5xy+20−q= \\ −x2−y2+6xy+20 \\ ⇒q=3x2−4y2+5xy+20− \\ (−x2−y2+6xy+20) \\ </u></strong></p><p><strong><u>[tex]3x2−4y2+5xy+20−q= \\ −x2−y2+6xy+20 \\ ⇒q=3x2−4y2+5xy+20− \\ (−x2−y2+6xy+20) \\ ⇒q=3x2−4y2+5xy+20+x2+y2−6xy−20 \\ </u></strong></p><p><strong><u>[tex]3x2−4y2+5xy+20−q= \\ −x2−y2+6xy+20 \\ ⇒q=3x2−4y2+5xy+20− \\ (−x2−y2+6xy+20) \\ ⇒q=3x2−4y2+5xy+20+x2+y2−6xy−20 \\ ⇒q=3x2+x2− \\ 4y2+y2+5xy− \\ 6xy+20−20 \\ </u></strong></p><p><strong><u>[tex]3x2−4y2+5xy+20−q= \\ −x2−y2+6xy+20 \\ ⇒q=3x2−4y2+5xy+20− \\ (−x2−y2+6xy+20) \\ ⇒q=3x2−4y2+5xy+20+x2+y2−6xy−20 \\ ⇒q=3x2+x2− \\ 4y2+y2+5xy− \\ 6xy+20−20 \\ ⇒q=4x2−3y2−xy+0 \\ </u></strong></p><p></p><p><strong><u>[tex]3x2−4y2+5xy+20−q= \\ −x2−y2+6xy+20 \\ ⇒q=3x2−4y2+5xy+20− \\ (−x2−y2+6xy+20) \\ ⇒q=3x2−4y2+5xy+20+x2+y2−6xy−20 \\ ⇒q=3x2+x2− \\ 4y2+y2+5xy− \\ 6xy+20−20 \\ ⇒q=4x2−3y2−xy+0$

$Hence, \\  4x2−3y2−xy  \\ should \: be \: subtracted.</u></strong></p><p></p><p><strong><u>[tex]Hence, \\  4x2−3y2−xy  \\ should \: be \: subtracted.$