Question

What should be taken away from 3x2square- 4y2square+5xy+20 to obtain-x2square-y2square+6xy+20?

Answer 1

➡HERE IS YOUR ANSWER⬇

We assume that p be taken away from the given expression (3x² - 4y² + 5xy + 20) to obtain (- x² - y² + 6xy + 20).

Then,


(3x² - 4y² + 5xy + 20) - p = (- x² - y² + 6xy + 20)

=> p = (3x² - 4y² + 5xy + 20) - (- x² - y² + 6xy + 20)

= 3x² - 4y² + 5xy + 20 + x² + y² - 6xy - 20

= (3 + 1)x² + (5 - 6)xy + (- 4 + 1)y²

= (4x² - xy - 3y²)

So, (4x² - xy - 3y²) should be taken away from the given expression (3x² - 4y² + 5xy + 20) to obtain (- x² - y² + 6xy + 20).

⬆HOPE THIS HELPS YOU⬅