Question

What should be taken away from 5x2–4y2+20 to obtain x2–3y2+10 ?​

Answer 1

Answer:

6x2- 7y2+30

Step-by-step explanation:

5x2-4y2+20 - x = x2- 3y2+ 10

x = x2 -3y2 +10 + 5x2 - 4y2 + 20

x = 6x2 - 7y2 + 30

Answer 2

Answer:

4x²-y²+10

Step-by-step explanation:

5x²-4y²+20- [x²–3y²+10]

= 5x²-4y²+20-x²+3y²-10

= 5x²-x²-4y²+3y²+20-10

= 4x²-y²+10

Hope it helped!

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