Question

What should be taken away from 5x2–4y2+20 to obtain x2–3y2+10 ?​

Answer 1

Answer:

4x2 - y2 + 10

Step-by-step explanation:

Let a be taken away from 5x2–4y2+20

5x2–4y2+20 - a = x2 - 3y2 + 10

- a = x2 - 3y2 + 10 -( 5x2–4y2+20 )

- a = x2 - 3y2 + 10 -5x2 + 4y2 - 20

-a = - 4x2 + y2 - 10

a = 4x2 - y2 + 10