Question

What should be taken away from 5x2 – 4y2 + 5xy + 20 to obtain

x

2 – 3y2 + 6xy + 10?​

Answer 1

Answer:

let's A should taken away

5x2-4y2+5xy+20-(A) =x2-3y2+6xy+10

A=5x2-4y2+5xy+20-x2+3y2-6xy-10

=4x2-y2-xy+10

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