What should be the acceleration of the box in which a block of mass m exerts a force mg/4 by the floor on the box?
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Answered by
38
R=mg/4
if the box is accelarting in down ward direction then
mg-N=ma
mg-mg/4=ma
3mg/4=ma
a=3mg/4m
a=3g/4
if the box is accelarting in down ward direction then
mg-N=ma
mg-mg/4=ma
3mg/4=ma
a=3mg/4m
a=3g/4
Answered by
3
Given : mass of the block m
Explanation:
As we know from Newton's second law of motion, F = M × a.
So, a =
since it accelerates then upward force is the psuedo force
and normal force and
downward force is Mg
then
N+Ma = Mg
therefore
thus the required acceleration is
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