Physics, asked by bhatjohn2296, 1 year ago

What should be the acceleration of the box in which a block of mass m exerts a force mg/4 by the floor on the box?

Answers

Answered by mushahid36
38
R=mg/4
if the box is accelarting in down ward direction then
mg-N=ma
mg-mg/4=ma
3mg/4=ma
a=3mg/4m
a=3g/4
Answered by isyllus
3

Given : mass of the block m

Explanation:

As we know from Newton's second law of motion, F = M × a.

So, a = \frac{F}{M}

since it accelerates then upward force is the psuedo force

and normal force and

downward force is Mg

then

N+Ma = Mg

therefore

\frac{Mg}{4}+Ma= Mg\\\\ \frac{g}{4}+a=g\\\\a = g-\frac{g}{4}\\\\a= \frac{3}{4}g

thus the required acceleration is \frac{3}{4}g

#Learn more :

https://brainly.in/question/10752112

Attachments:
Similar questions