Question

What should be the acceleration of the box in which a block of mass m exerts a force mg/4 by the floor on the box?

Answer 1

R=mg/4
if the box is accelarting in down ward direction then
mg-N=ma
mg-mg/4=ma
3mg/4=ma
a=3mg/4m
a=3g/4

Answer 2

Given : mass of the block m

Explanation:

As we know from Newton's second law of motion, F = M × a.

So, a = $\frac{F}{M}$

since it accelerates then upward force is the psuedo force

and normal force and

downward force is Mg

then

N+Ma = Mg

therefore

$\frac{Mg}{4}+Ma= Mg\\\\ \frac{g}{4}+a=g\\\\a = g-\frac{g}{4}\\\\a= \frac{3}{4}g$

thus the required acceleration is $\frac{3}{4}g$

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