What should be the average velocity of water in a tube of radius 0.005 m so that the flow is just turbulent? The viscosity of water is 0.001 Pa-s
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Answered by
35
Hi
Here is your answer,
Here r = 0.005 m , diameter D =2r = 0.010 m
η = 0.001 Pa⁻s , ρ = 1000 kgm⁻³
For flow to be just turbulent, Re = 3000
∴ v = Re η/ρD = 3000 × 0.001/1000 × 0.010 = 0.3 ms⁻¹
∴ Viscous force on the drop, ( According to Stoke's Law)
F = 6πηrv
= 6 × 3.14 × 1.8 × 10⁻⁵ × 2 × 10⁻⁵ × 5.8 × 10⁻²
= 3.94 × 10⁻¹⁰ N
Hope it helps you !
Here is your answer,
Here r = 0.005 m , diameter D =2r = 0.010 m
η = 0.001 Pa⁻s , ρ = 1000 kgm⁻³
For flow to be just turbulent, Re = 3000
∴ v = Re η/ρD = 3000 × 0.001/1000 × 0.010 = 0.3 ms⁻¹
∴ Viscous force on the drop, ( According to Stoke's Law)
F = 6πηrv
= 6 × 3.14 × 1.8 × 10⁻⁵ × 2 × 10⁻⁵ × 5.8 × 10⁻²
= 3.94 × 10⁻¹⁰ N
Hope it helps you !
Answered by
7
Answer:
3.94 ×10^-4
Explanation:
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