what should be the boiling point of 1 molal aqueoud kcl sloution
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i=2,because Nacl dissociates into two ions in aqueous solution of Nacl
change in Tb=Tb-Tb°=Kb×m×i
Tb-373=0.52×1×2
Tb=1.04+373
Tb=374.04
so,boiling point is 374.04k temparature
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