What should be the charge on a sphere of radius 2 cm so that when it is brought in contact with another sphere of radius 5cm carrying a charge of 10 microcoulomb, there is no net transfer of charge between the spheres.
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The charge on a sphere of radius 2 cm so that when it is brought in contact with another sphere of radius 5 cm carrying a charge of 10 micro coulombs is 4 * 10⁻⁶ C.
Explanation:
We are given that there is no net transfer of charge between the spheres, so, both the spheres will have same potential energy which is denoted as “V”.
Step 1: For the sphere of radius, r1 = 5 cm = 0.05 m
Charge for the this sphere is given, q1 = 10 µC = 10 * 10⁻⁶ = 10⁻⁵ C
The potential energy “V” is given as,
V = [Kq1] / r1 …… [columbs constant K = 9 * 10⁹ Nm²/C²]
⇒ V = (9 x 10⁹ x 10⁻⁵) / 0.05
⇒ V = 1.8 * 10⁶ V
Step 2: For the sphere of radius, r2 = 2 cm = 0.02 m
Let the charge on the sphere of radius 0.02 m be denoted as “q2” Columb.
Thus,
The charge “q2” on the sphere of radius 0.02 m will be,
= [V * r2] / K
= [1.8 * 10⁶ * 0.02] / 9 x 10⁹
= 4 * 10⁻⁶ C
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