Question

what should be the coefficient of friction between the tyre and road when a car travelling 60 km/hr makes a level turn of a radius 40 m​

Answer 1

Here is your answer mate

Here 60km/h is converted into m/s ohk so I multiply 5/8 to it ohk

hope it's help you

Answer 2

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Hello friend, here is ur answer

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Given

speed of car , v = 60km/h

radius of turn, r = 40m

Centripetal force=Force of friction

mv²/r=mg×u

u=v²/r×g

u=60×60/18×18×40×10

u=0.694

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u=0.71

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hey friend, it is right answer of ur question

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u can check the Google

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same answer u found there

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