Question

What should be the diameter of a water drop so that the excces pressure inside it is 80 N per meter square ( surface tension of water = 7.27 × 10 raise to 2 N per meter

Answer 1

Explanation:

ANSWER

Given : S=0.072 N/m

Diameter of water drop D=1.2mm=0.012 m

Thus radius of drop r=

2

0.012

=0.006 m

Excess pressure inside water drop ΔP=

r

2S

∴ ΔP=

0.006

2×0.072

=24 N/