Question

what should be the energy in the first excited state of beryllium^3+?? PPS HELP ANSWER WITH EXPLAINATION

Answer 1

first understand that we can only calculate energy of single electron species (charged atom) .As you know Be3+ has one electron only . we can calculate energy in n th orbit = -13.6 ×Z2/n2 where Z is atomic number and n is the number of the orbit . first excited state means 2nd orbit .Z of Beryllium is 4. so energy =-13.6 ×16/4 = -54.4 eV sorry I didn't mention the unit earlier please mark me as brainliest

Answer 2

Answer:54.4ev

.Explanation:formula for energy in evolts is = 13.6  *z2\  n2

then first excited stage means 2nd orbital  hence 13.6 *2*2/1*1

=54.4ev