Physics, asked by nick6993, 1 year ago

What should be the frequency of oscillation of a simple pendulum mounted in a cabin that is freely falling under gravity?

Answers

Answered by sahil1531
2

HERE COMES THE ANS:-

T= 2π √ L /g

As WE HAVE TO FIND FREQ:-

WHICH IS INVERSE OF T=

THERE BY WE HAVE REVERSE THE FORMULA =

f= 1/2π √ g/L

⏩⏩⏩BUT AS DISCUSED IN QUESTION FALLING FRELY MEANS

❗❗ gravity becomes infinite there by =

g~ f

so f= Infinite ❤❤

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