What should be the pressure inside a small air bubble of 0.1 mm radius situated just below the surface of water? Surface tension of water = 7.2×10 N/m and atmospheric pressure = 1013×10¹ N/m ²
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Answer:
The pressure inside a small air bubble of radius 0.1mm situated just below the surface of water will be equal to [Take surface tension of water 70xx10^-3Nm^-1 and atmospheric pressure=1.013xx10^5Nm^-2]
Answered by
1
Given that,
Radius of air bubble r=0.1mm=10
−3
m
Surface tension of water T=72×10
−3
N/m
Atmospheric pressure P
atm
=1.013×10
5
N/m
2
We know that,
The excess pressure inside the air bubble is given by P
2
−P
1
=
R
2T
∴ Pressure inside the air bubble P
2
=P 1+ R2T
Substituting the values, we have P
2
=1.013×10 5 + 10 −4
2×7.2×10 −2
=1.027×10 5
N/m 2
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