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A garrison of 120 men has provision for 30 days. At the end of five days, five more
men joined them. How many days can they sustain on the remaining provision?
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We know that no. of days is inversely propotional to the provision for men.
So for 120 men the provision would last for 30days. (given)
Therefore, the provision for 1 men would sustain for. 120 *30 = 3600 days.
Let after the joining of 5 men (after 5 days) the no of more days the provision would last is x days
A.t.q 120*30 = 120*5+125*x
(120*30) - (120*5)= 125x
120(30-5)=125x
120 * 25 = 125x
120 = 5x
x=120/5
x= 24
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