what should be the speeds of two persons such that when they move uniformly towards each other, they get 3.0 m closer each second, and when they move uniformly in the same direction with the original speeds, they get 3.0 m closer every 10 sec
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let the speeds of two persons be x and y,
in the first case both are moving towards each other and the distance between them is decreasing as 3m per second ,the distance moved by 1 person in 1 second is speed × time=x×1=x,in the same way distance moved by 2 person in 1 second is y,so
x+y=3-----1 st equation
in second case each are moving in same direction
and the distance between them is decreasing as 3m per 10 sec,distance moved by 1 person in 10sec is 10x and by 2 person is 10y
let us assume that x is more than y
so 10x- 10y=3-------2 nd equation
solving 1 and 2 we get x=33/20=1.65m/s, y=27/20=1.35m/s
in the first case both are moving towards each other and the distance between them is decreasing as 3m per second ,the distance moved by 1 person in 1 second is speed × time=x×1=x,in the same way distance moved by 2 person in 1 second is y,so
x+y=3-----1 st equation
in second case each are moving in same direction
and the distance between them is decreasing as 3m per 10 sec,distance moved by 1 person in 10sec is 10x and by 2 person is 10y
let us assume that x is more than y
so 10x- 10y=3-------2 nd equation
solving 1 and 2 we get x=33/20=1.65m/s, y=27/20=1.35m/s
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