what should be the temp. rise of a bras rod (α=2* 10 to the power -5)so as to increase its lenghth by 1%.plzz..... ans as fast as u can
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thermal expansion
ΔL = α * L * ΔT
ΔL / L = 1/100
so ΔT = 1/(100 * 2 * 10⁻⁵)
= 500° K
ΔL = α * L * ΔT
ΔL / L = 1/100
so ΔT = 1/(100 * 2 * 10⁻⁵)
= 500° K
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