What should be the temperature (in °C ) for a gas with 240 ml volume at 30°C to occupy one third of its volume? The pressure is kept constant.
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Temperature for given condition should be 10° C.
The question can be solved by application of Charle's law. Charle's law states that "the volume of an ideal gas at constant pressure is directly proportional to the absolute temperature."
It is given by the relation -
V1/T1 = V2/T2
V represents volume and t represents temperature.
Given values in question are -
V1 = 240ml
V2 = 1/3*240
V2 = 80 ml
T1 = 30°C
T2 is the temperature be calculated.
According to given relation,
240/30 = 80/T2
T2 = 10°C
Thus, temperature will be 10° C
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