Question

what should be the value of k if 8x square -4x-k= where x =-3​

Answer 1

Answer:

$k = -24$

Step-by-step explanation:

$8x^{2} -4x-k=0$

Given, x = -3

$-4(-3)^2-4(-3)-k = 0$

$-36 + 12 - k = 0$

$k = -24$