Question

What should be the value of Kc for the reaction 2SO2 +O2 gives 2SO3,if amounts are SO3 48 g,SO2 12.8 g and O2 9.6 at equilibrium and Volume of container is 1 litre?

Answer 1

"The value of Kc for the reaction can be calculated by a formulae which will give us the exact value

First, we calculate the number of moles of different compounds

O2 = 0.6

SO3 = 0.6

SO2 = 0.2

Since the volume is 1 ltr, the concentration will remain the same.

Thus Kc = 0.62 / 0.22 * 0.6 =

Kc = 15

"

Answer 2

Answer:

48g of SO3 , 12.8g of  SO2 and 9.6g of O2 is present in the mixture.

We calculate the no.of moles of SO3, SO2 and O2 as  

O2 = 9.6/16 = 0.6

SO3 = 48/80.1 = 0.6

SO2 =12.8/64 = 0.2

Since volume is given , we calculate the concentration by dividing the no.of moles by the volume.

So Volume = 1L

O2 = 0.6/1 =0.6

SO3 =  0.6/1 = 0.6

SO2 = 0.2/1 = 0.2

Kc = [SO3]2[SO2]2[O2]     =[0.6]2[0.2]2 [0.6]    Kc  = 15

Explanation: