Math, asked by shrijithsacharya, 5 months ago

What should be the value of p, if 2x^2 - px +4 =0, when x=1. * pls say how to do

Answers

Answered by ABAditya17
5

Answer:

The value of p is 6 units

Step-by-step explanation:

2x^2 - px + 4 = 0

Put x = 1 in the given equation

2(1)^2 - p(1) + 4 = 0

2(1) - p + 4 =0

2 + 4 - p = 0

6 = p

p = 6

Answered by kaurarmeen2
0

Answer:

The value of p is 6 units

Step-by-step explanation:

2x^2 - px + 4 = 0

Put x = 1 in the given equation

2(1)^2 - p(1) + 4 = 0

2(1) - p + 4 =0

2 + 4 - p = 0

6 = p

p = 6

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