Question

What should be the value of p if the value of 3y^2-9y-p equal to 8 when y= -2

Plz help....​

Answer 1

3y²-9y-p=8

or,3×(-2)²-9×(-2)-p=8

or,3×4+18-p=8

or,12+18-p=8

or,30-8=p

∴ p=22

HOPE IT HELPED :)

Answer 2

3y^2-9y-p=8

y=-2

3(-2)^2-9(-2)-p=8

12+18-p=8

30-p=8

-p=8-30

-p=-22

p=22