Question

What should be the value of the expression if a=1, e=2? (2 marks )
9a² + 12ae – 17ae – 2a– 7a² + 5 – 13​

Answer 1

Given :

9a² + 12ae – 17ae – 2a– 7a² + 5 – 13, a=1,e=2

Solution :

$\sf \rightarrow 9a^2+12ae-17ae-2a-7a^2+5-13$

$\sf \rightarrow9(1)^2+12(1)(2)-17(1)(2)-2(1)-7(1)^2+5-13$

$\sf \rightarrow 9(1)+12(2)-17(2)-2(1)-7(1)+5-13$

$\rightarrow\sf 9+24-34-2-7+5-13$

$\rightarrow\sf 9+24+5-34-2-7-13$

$\rightarrow \sf 33+5-36-20$

$\rightarrow \sf 38-56 \implies -18$

Required Answer :

$\boxed{\sf 9a^2+12ae-17ae-2a-7a^2+5-13= -18}$